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2013-06-01 06:31:31 +0200 asked a question I am trying to solve recurring deposite equation but answer is another equation,please help

Following is the problem I am trying to solve


x = var('x')
solve(10000*(1+(0.0825/4))^(x*4)==400000,x)
 

but instead of value of x I am getting


[1633^x == I*40^(1/4)*1600^x, 1633^x == -40^(1/4)*1600^x, 1633^x == -I*40^(1/4)*1600^x, 1633^x == 40^(1/4)*1600^x]
 

Please advise how to solve this!