Iftikhar Burhanuddin's profile - activity

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2018-06-17 12:34:31 -0500	received badge	● Notable Question (source)
2015-09-24 06:33:55 -0500	received badge	● Popular Question (source)
2012-11-26 12:59:40 -0500	asked a question	bug in sqrt? This looks like a bug. `sage: 1/sqrt(10) 1/10*sqrt(10)` On the other hand, `sage: 1/sqrt(9) 1/3` works fine.
2012-11-10 17:41:27 -0500	commented question	Bug in legend_label of list_plot? On the other hand, `(X+Y).save('tmp.eps')` displays the legend labels correctly.
2012-11-10 17:37:55 -0500	commented answer	Bug in legend_label of list_plot? How do I circumvent this bug to get the legend labels right?
2012-11-10 16:48:53 -0500	answered a question	Creating a polynomial ring where the variables are code generated Thanks for the answers.
2012-11-10 16:44:35 -0500	asked a question	Bug in legend_label of list_plot? Hi, Suppose `lstR` and `lstS` are two lists of real numbers. `X = list_plot(lstR, plotjoined = True, color='black', marker = 'o', linestyle="-", legend_label='$R$', axes_labels=['Trial number', 'Value']) Y = list_plot(lstS, plotjoined = True, color='black', marker = 's', linestyle="--", legend_label='$S$', axes_labels=['Trial number', 'Value']) (X+Y).show()` The legend label for R is two squares joined by a line instead of two circles joined by a line. Is this a bug? (I am unable to upload the plot image because my karma is not > 60.)
2012-11-06 03:31:28 -0500	received badge	● Supporter (source)
2012-11-06 02:41:09 -0500	received badge	● Editor (source)
2012-11-06 02:14:46 -0500	asked a question	Creating a polynomial ring where the variables are code generated Hi, The standard way to create a multivariate polynomial ring over `ZZ` is as follows. `sage: R.<x,y> = PolynomialRing(ZZ)` I want to create a polynomial ring over `ZZ` where the variables are generated by code. `sage: n = 5 sage: lstx = list(var('x_%d' % i) for i in range(n)) sage: lstx [x_0, x_1, x_2, x_3, x_4]` My attempts at creating the desired ring whose variables are the elements of `lstx` result in error. Any help will be appreciated.