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I typed

n = var('n')

sum(1/((2n-1)^2(2n+1)^2(2*n+3)^2), n, 0, oo)

sage answered

3/256*pi^2 - 1/32

By hand computation (via Fourier series), and by WolframAlpha I got

3/256*pi^2

Why?

Link to WolframAlpha's result.

(This is my first question. If it is inappropriate here, please tell me where I should ask it. I used the tag "bug", but I of course mean "potential bug". Thank you very much in advance!)

I typed

n = var('n')
var('n')
  
sum(1/((2n-1)^2(2n+1)^2(2*n+3)^2), sum(1/((2*n-1)^2*(2*n+1)^2*(2*n+3)^2), n, 0, oo)oo)

3/256*pi^2 - 1/32
1/32

I typed

n = var('n')

sum(1/((2*n-1)^2*(2*n+1)^2*(2*n+3)^2), n, 0, oo)

sage answered

3/256*pi^2 - 1/32

By hand computation (via Fourier series), and by WolframAlpha I got

3/256*pi^2

Why?

Link to WolframAlpha's result.

(This is my first question. If it is inappropriate here, please tell me where I should ask it. I used the tag "bug", but I of course mean "potential bug". Thank you very much in advance!)

I typed

n = var('n')

sum(1/((2*n-1)^2*(2*n+1)^2*(2*n+3)^2), n, 0, oo)

sage answered

3/256*pi^2 - 1/32

By hand computation (via Fourier series), and by WolframAlpha I got

3/256*pi^2

Why?

Link to WolframAlpha's result.

(This is my first question. If it is inappropriate here, please tell me where I should ask it. I used the tag "bug", but I of course mean "potential bug". Thank you very much in advance!)

I typed

n = var('n')

sum(1/((2*n-1)^2*(2*n+1)^2*(2*n+3)^2), n, 0, oo)

sage answered

3/256*pi^2 - 1/32

By hand computation (via Fourier series), and by WolframAlpha I got

3/256*pi^2

Why?

Link to WolframAlpha's result.

(This is my first question. If it is inappropriate here, please tell me where I should ask it. I used the tag "bug", but I of course mean "potential bug". Thank you very much in advance!)