suppose I have a normalized vector perpendicular to a plane like
$x = \frac{(2i+3j+k)}{\sqrt{14}}$ , how can I find a rotation matrix A, such that it rotates x into the xy plane like so:
$Ax = y = \frac{(i, j)} {\sqrt{2}}$
| 1 | initial version |
suppose I have a normalized vector perpendicular to a plane like
$x = \frac{(2i+3j+k)}{\sqrt{14}}$ , how can I find a rotation matrix A, such that it rotates x into the xy plane like so:
$Ax = y = \frac{(i, j)} {\sqrt{2}}$
| 2 | No.2 Revision |
suppose I have a normalized vector perpendicular to a plane like
$x = \frac{(2i+3j+k)}{\sqrt{14}}$ , how can I find a rotation matrix A, such that it rotates x into the xy plane like so:
$Ax = y = \frac{(i, j)} {\sqrt{2}}$
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