The system is written on the form Ax=0. I know this can be done by using, for example,
solve([eq1==0,eq2==0],x1,x2)
But this is somewhat complex. I wonder if the system can be directly solved by A.solve_right or some other simpler notation?
![]() | 1 | initial version | |
The system is written on the form Ax=0. I know this can be done by using, for example,
solve([eq1==0,eq2==0],x1,x2)
But this is somewhat complex. I wonder if the system can be directly solved by A.solve_right or some other simpler notation?
![]() | 2 | retagged |
The system is written on the form Ax=0. I know this can be done by using, for example,
solve([eq1==0,eq2==0],x1,x2)
But this is somewhat complex. I wonder if the system can be directly solved by A.solve_right or some other simpler notation?