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y = x /. NSolve[LegendreP[i, x] == 0, x]; z = (2 (1 - y^2))/((i + 1)^2 LegendreP[i + 1, y]^2);

and

NumberForm[N[!( *SubsuperscriptBox[([Integral]), (-1), (1)](f[ x] [DifferentialD]x))], 12]

Please help me translate this into SAGE. Thank You!!

y = x /. NSolve[LegendreP[i, x] == 0, x]; z = (2 (1 - y^2))/((i + 1)^2 LegendreP[i + 1, y]^2);

and

NumberForm[N[!( *SubsuperscriptBox[([Integral]), (-1), (1)](f[ x] [DifferentialD]x))], 12]

Edit: I think the OP means $$\int_{-1}^1 f(x)\;dx$$

Please help me translate this into SAGE. Thank You!!

Edit: I think the OP means $$\int_{-1}^1 f(x)\;dx$$

Edit: I think the OP means $$\int_{-1}^1 f(x)\;dx$$

y = x /. NSolve[LegendreP[i, x] == 0, x]; z = (2 (1 - y^2))/((i + 1)^2 LegendreP[i + 1, y]^2);

and

NumberForm[N[!( *SubsuperscriptBox[([Integral]), (-1), (1)](f[ x] [DifferentialD]x))], 12]

Edit: I think the OP means $$\int_{-1}^1 f(x)\;dx$$

Please help me translate this into SAGE. Thank You!!

y = x /. NSolve[LegendreP[i, x] == 0, x]; z = (2 (1 - y^2))/((i + 1)^2 LegendreP[i + 1, y]^2);

and

NumberForm[N[!( *SubsuperscriptBox[([Integral]), (-1), (1)](f[ x] [DifferentialD]x))], 12]

Edit: I think the OP means $$\int_{-1}^1 f(x)\;dx$$

y = x /. NSolve[LegendreP[i, x] == 0, x]; z = (2 (1 - y^2))/((i + 1)^2 LegendreP[i + 1, y]^2);

and

NumberForm[N[!( *SubsuperscriptBox[([Integral]), (-1), (1)](f[ x] [DifferentialD]x))], 12]

Edit: I think the OP means $$\int_{-1}^1 f(x)\;dx$$