I didn't find the way to define an involution on the free algebra (say in two generators) yet. I'm happy if I can deal with unitary elements. So I add two variables, $y$ and $z$ which serve as $w^\star,x^\star$ and force a relation so that $wy=1=()$, the empty word, and similar relation $zx=1=()$ . But then typing
A.<w,x,y,z> = FreeAlgebra(QQ,4)
G=A.g_algebra({w*y: 1})
(x,y,z) = G.gens()
yields an error (#This is dirty, coercion is broken). That is: Question: which is the free algebra empty word here?
Of course, I tried to add a symbol $E$ which then satisfies $E*g$ for all the generators $g$, But then
G=A.g_algebra({w*y: E})
yields also an error.
/usr/lib/python3/dist-packages/sage/algebras/free_algebra.py in g_algebra(self, relations, names,
order, check)
873 d_poly = commuted - self(c) * self(m)
874 break
--> 875 assert c_coef is not None, list(m)
876 v2_ind = self.gens().index(v2)
877 v1_ind = self.gens().index(v1)AssertionError: [(E, 1)]
Second question: does somebody know an easier way to to implement the involution here?