R.<x> = SR[]
a = SR.var('a')
P = a*x
P.subs(a=1)
returns x, as expected, but
R.<x, y> = SR[]
a = SR.var('a')
P = a*x
P.subs(a=1)
returns a*x.
Revision history [back]
 | 1 | initial version |
Substitution of variable in polynomial not working as expected.
Substitution of variable in polynomial not working as expected.
The subs method behaves differently in two related settings:
- univariate polynomials over SR
- multivariate polynomials over SR
when trying to substitute a value for some variable involved as a coefficient.
In the univariate case:
R.<x> = SR[]
a = SR.var('a')
P = a*x
P.subs(a=1)
returns x, x, as expected, but expected.
But in the multivariate case:
R.<x, y> = SR[]
a = SR.var('a')
P = a*x
P.subs(a=1)
returns a*x. a*x.
| | 3 | retagged |
Substitution of variable in polynomial not working as expected.
The subs method behaves differently in two related settings:
- univariate polynomials over SR
- multivariate polynomials over SR
when trying to substitute a value for some variable involved as a coefficient.
In the univariate case:
R.<x> = SR[]
a = SR.var('a')
P = a*x
P.subs(a=1)
returns x, as expected.
But in the multivariate case:
R.<x, y> = SR[]
a = SR.var('a')
P = a*x
P.subs(a=1)
returns a*x.
