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asked 2 years ago

matrixman gravatar image

finding conjugating element for two conjugate permutations

Suppose a and b are elements of a symmetric group that are conjugate, how to find a conjugating element in sage?

For example,

G=SymmetricGroup(3); a=G((1,2)) b=G((2,3))

Then

G.conjugacy_class(a) == G.conjugacy_class(b)

is true, but is there a function to give x such that xa=bx?

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updated 2 years ago

Max Alekseyev gravatar image

finding conjugating element for two conjugate permutations

Suppose a and b are elements of a symmetric group that are conjugate, how to find a conjugating element in sage?

For example,

G=SymmetricGroup(3);
a=G((1,2))
b=G((2,3))

b=G((2,3))

Then

G.conjugacy_class(a) == G.conjugacy_class(b)

G.conjugacy_class(b)

is true, but is there a function to give x x such that xa=bx?xa==bx?