Is the number of terms of a Laurent series fixed? E.g.
P.<t> = LaurentSeriesRing(QQ)
1/P([1 for t in range(100)])
yields
1 - t + O(t^20)
and not
1 - t + O(t^100)
as expected. There seems to be no simple way of setting the "precision" of the series. Or is there ... ?