Hello

I want to take linear distance beetween two points on Eliptic curve:

curve : y2=x3+7 secp256k1

p_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE FFFFFC2F'
p = ZZ( '0x' + p_string.replace(' ', ''))
p
E = EllipticCurve( GF(p), [0, 7] )  
E
n_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE BAAEDCE6 AF48A03B BFD25E8C D0364141'
n = ZZ( '0x' + n_string.replace(' ', '') )



xP = 0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798
yP = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
P = E.point( (xP, yP) ) # Generator point

Point no 1:

p_1_x=0x28f3c7982219bf067d9723a54bef8e0ae7d970b4285a148685ce98819bd59c99
p_1_y=0x3da6945a85ba67249e96534f3cb93af144301e3ef03f848ebf17fedd55addd14
P1 = E.point( (p_1_x, p_1_y) )

Point no 2:

p_2_x=0xc69b120facc137ad7ecf7407b97f3e1bcecec27ed6617ad1e3bb4f5a265c2230
p_2_y=0xdab461d8de9d194b9aae05cf3fc361e31b0cd172985720a9963a1fd9cb4dab13
P2 = E.point( (p_2_x, p_2_y) )

calculation : perform add or mult for equal :

P1_mult = P1 * 82096204097375626523300693245739453783745399685178560726932375997561515334942 =
P1_mult result= 
(46471116781602954419346378639681376672332207911597631846166461640126253045935 : 115074167981782238568697336312618123980176908468606887399010690362202000326798 : 1)

P2_add = P2 + 29894233847412895230616850443375888414306408440111129860511310128693381347651 * P

P2_add result: 
(46471116781602954419346378639681376672332207911597631846166461640126253045935 : 115074167981782238568697336312618123980176908468606887399010690362202000326798 : 1)

so P1_mult = P2_add so what is linear distance in integer beetween P1 and P2 if we know above information?

at the moment no idea, any tips, solution, How to do?

Hello

I want to take linear distance beetween two points on Eliptic curve:

curve : y2=x3+7 secp256k1

p_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE FFFFFC2F'
p = ZZ( '0x' + p_string.replace(' ', ''))
p
E = EllipticCurve( GF(p), [0, 7] )  
E
n_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE BAAEDCE6 AF48A03B BFD25E8C D0364141'
n = ZZ( '0x' + n_string.replace(' ', '') )



xP = 0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798
yP = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
P = E.point( (xP, yP) ) # Generator point

We have two point on curve y2=x3+7 secp256k1 with above parameter.

Point no 1:

p_1_x=0x28f3c7982219bf067d9723a54bef8e0ae7d970b4285a148685ce98819bd59c99
p_1_y=0x3da6945a85ba67249e96534f3cb93af144301e3ef03f848ebf17fedd55addd14
P1 = E.point( (p_1_x, p_1_y) )

Point no 2:

p_2_x=0xc69b120facc137ad7ecf7407b97f3e1bcecec27ed6617ad1e3bb4f5a265c2230
p_2_y=0xdab461d8de9d194b9aae05cf3fc361e31b0cd172985720a9963a1fd9cb4dab13
P2 = E.point( (p_2_x, p_2_y) )

P1 it is p1 * P ( integer * Generator)
P2 it is p2 * P ( integer * Generator)

calculation : perform add or mult for equal :

P1_mult = P1 * 82096204097375626523300693245739453783745399685178560726932375997561515334942 =
P1_mult result= 
(46471116781602954419346378639681376672332207911597631846166461640126253045935 : 115074167981782238568697336312618123980176908468606887399010690362202000326798 : 1)

P2_add = P2 + 29894233847412895230616850443375888414306408440111129860511310128693381347651 * P

P2_add result: 
(46471116781602954419346378639681376672332207911597631846166461640126253045935 : 115074167981782238568697336312618123980176908468606887399010690362202000326798 : 1)

so P1_mult = P2_add P2_add

P1 == P2 as P1_mult and P2_add , after calculation so from this expression can we calculate what is P1-P2? so what is linear distance in integer beetween P1 and P2 if we know above information?

at the moment no idea, any tips, solution, How to do?

Hello

I want to take linear distance beetween two points on Eliptic curve:

curve : y2=x3+7 secp256k1

p_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE FFFFFC2F'
p = ZZ( '0x' + p_string.replace(' ', ''))
p
E = EllipticCurve( GF(p), [0, 7] )  
E
n_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE BAAEDCE6 AF48A03B BFD25E8C D0364141'
n = ZZ( '0x' + n_string.replace(' ', '') )



xP = 0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798
yP = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
P = E.point( (xP, yP) ) # Generator point

We have two point on curve y2=x3+7 secp256k1 with above parameter.

Point no 1:

p_1_x=0x28f3c7982219bf067d9723a54bef8e0ae7d970b4285a148685ce98819bd59c99
p_1_y=0x3da6945a85ba67249e96534f3cb93af144301e3ef03f848ebf17fedd55addd14
P1 = E.point( (p_1_x, p_1_y) )

Point no 2:

p_2_x=0xc69b120facc137ad7ecf7407b97f3e1bcecec27ed6617ad1e3bb4f5a265c2230
p_2_y=0xdab461d8de9d194b9aae05cf3fc361e31b0cd172985720a9963a1fd9cb4dab13
P2 = E.point( (p_2_x, p_2_y) )

and we want to know what is P1-P2.

P1 it is p1 * P ( integer * Generator)
P2 it is p2 * P ( integer * Generator)

so : (p1P) - (p2P), but we don't know p1 and p2 , we know only P1 and P2 as point on curve.

but we know when the 2 points P1 and P2 are equal .

the question is there any way to verify and take value P1-P2 as integer ?

calculation : perform add or mult for equal :

a= 82096204097375626523300693245739453783745399685178560726932375997561515334942 
P1_mult = P1 * 82096204097375626523300693245739453783745399685178560726932375997561515334942 =
P1_mult result= 
(46471116781602954419346378639681376672332207911597631846166461640126253045935 : 115074167981782238568697336312618123980176908468606887399010690362202000326798 : 1)
a

b= 29894233847412895230616850443375888414306408440111129860511310128693381347651 
P2_add = P2 + 29894233847412895230616850443375888414306408440111129860511310128693381347651 * b* P

P2_add result: 
(46471116781602954419346378639681376672332207911597631846166461640126253045935 : 115074167981782238568697336312618123980176908468606887399010690362202000326798 : 1)

so P1_mult = == P2_add

P1 == P2 as P1_mult and P2_add , after calculation so from this expression can we calculate what is P1-P2? so what is linear distance in integer beetween P1 and P2 if we know above information?

at the moment no idea, any tips, solution, How to do?

Hello

I want to take linear distance beetween two points on Eliptic curve:

curve : y2=x3+7 secp256k1

p_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE FFFFFC2F'
p = ZZ( '0x' + p_string.replace(' ', ''))
p
E = EllipticCurve( GF(p), [0, 7] )  
E
n_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE BAAEDCE6 AF48A03B BFD25E8C D0364141'
n = ZZ( '0x' + n_string.replace(' ', '') )



xP = 0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798
yP = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
P = E.point( (xP, yP) ) # Generator point

We have two point on curve y2=x3+7 secp256k1 with above parameter.

Point no 1:

p_1_x=0x28f3c7982219bf067d9723a54bef8e0ae7d970b4285a148685ce98819bd59c99
p_1_y=0x3da6945a85ba67249e96534f3cb93af144301e3ef03f848ebf17fedd55addd14
P1 = E.point( (p_1_x, p_1_y) )

Point no 2:

p_2_x=0xc69b120facc137ad7ecf7407b97f3e1bcecec27ed6617ad1e3bb4f5a265c2230
p_2_y=0xdab461d8de9d194b9aae05cf3fc361e31b0cd172985720a9963a1fd9cb4dab13
P2 = E.point( (p_2_x, p_2_y) )

and we want to know what is P1-P2.

P1 it is p1 * P ( integer * Generator)
P2 it is p2 * P ( integer * Generator)

so : (p1P) - (p2P), but we don't know p1 and p2 , we know only P1 and P2 as point on curve.

but we know when the 2 points P1 and P2 are equal .

the question is there any way to verify and take value P1-P2 as integer ? for example : if p1=5 and p2 =9 , then p1-p2 or P1-P2 = -4

calculation : perform add or mult for equal :

a= 82096204097375626523300693245739453783745399685178560726932375997561515334942 
P1_mult = P1 * a

b= 29894233847412895230616850443375888414306408440111129860511310128693381347651 
P2_add = P2 + b* P

so P1_mult == P2_add

P1 == P2 as P1_mult and P2_add , after calculation so from this expression can we calculate what is P1-P2? so what is linear distance in integer beetween P1 and P2 if we know above information?

at the moment no idea, any tips, solution, How to do?

Hello

I want to take linear distance beetween two points on Eliptic curve:

curve : y2=x3+7 secp256k1

p_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE FFFFFC2F'
p = ZZ( '0x' + p_string.replace(' ', ''))
p
E = EllipticCurve( GF(p), [0, 7] )  
E
n_string = 'FFFFFFFF FFFFFFFF FFFFFFFF FFFFFFFE BAAEDCE6 AF48A03B BFD25E8C D0364141'
n = ZZ( '0x' + n_string.replace(' ', '') )



xP = 0x79be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798
yP = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
P = E.point( (xP, yP) ) # Generator point

We have two point on curve y2=x3+7 secp256k1 with above parameter.

Point no 1:

p_1_x=0x28f3c7982219bf067d9723a54bef8e0ae7d970b4285a148685ce98819bd59c99
p_1_y=0x3da6945a85ba67249e96534f3cb93af144301e3ef03f848ebf17fedd55addd14
P1 = E.point( (p_1_x, p_1_y) )

Point no 2:

p_2_x=0xc69b120facc137ad7ecf7407b97f3e1bcecec27ed6617ad1e3bb4f5a265c2230
p_2_y=0xdab461d8de9d194b9aae05cf3fc361e31b0cd172985720a9963a1fd9cb4dab13
P2 = E.point( (p_2_x, p_2_y) )

and we want to know what is P1-P2.

P1 it is p1 * P ( integer * Generator)
P2 it is p2 * P ( integer * Generator)

so : (p1P) - (p2P), but we don't know p1 and p2 , we know only P1 and P2 as point on curve.

but we know when the 2 points P1 and P2 are equal .

the question is there any way to verify and take value P1-P2 as integer ? for example : if p1=5 and p2 =9 , then p1-p2 or P1-P2 = -4

calculation : perform add or mult for equal :

a= 82096204097375626523300693245739453783745399685178560726932375997561515334942 
P1_mult = P1 * a

b= 29894233847412895230616850443375888414306408440111129860511310128693381347651 
P2_add = P2 + b* P

so P1_mult == P2_add

P1 == P2 as P1_mult and P2_add , after calculation so from this expression can we calculate what is P1-P2? so what is linear distance in integer beetween P1 and P2 if we know above information?

at the moment no idea, any tips, solution, How to do?