Revision history [back]

solve result contain variable which to solved

Hi!

I'm newbie with solve please help me what I doing wrong!

I do: (a,l,x) = var('a,l,x') solve(1/(a(x-1))==(sqrt(x^2+1^2)/2/l),x) --> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params (a,l,x) = var('a,l,x') a=24 l=1.28 solve(1/(a(x-1))==(sqrt(x^2+1^2)/2/l),x) --> [x == 1/75(75*sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Thanks for help.

solve result contain variable which to solved

Hi!

I'm newbie with ~~solve please~~ sageplease help me what I doing wrong!

I do: (a,l,x) = var('a,l,x') ~~solve(1/(a(x-1))==(sqrt(x^2+1^2)/2/l),x) -->~~ solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)a)]1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params (a,l,x) = var('a,l,x') a=24 l=1.28 ~~solve(1/(a(x-1))==(sqrt(x^2+1^2)/2/l),x) -->~~ solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75~~(75*sqrt(x^2~~ sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the eqution by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x) the solve() function give me the roots well.

Thanks for help.

3
None

updated 2020-11-21 16:26:27 +0100

solve result contain variable which to solved

Hi!

I'm newbie with sageplease help me what I doing wrong!

I do: (a,l,x) = var('a,l,x') solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params (a,l,x) = var('a,l,x') a=24 l=1.28 solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the eqution by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x) the solve() function give me the roots well.

Thanks for help.

4
None

updated 2020-11-21 16:26:56 +0100

solve result contain variable which to solved

Hi!

I'm newbie with sageplease help me what I doing wrong!

I do: (a,l,x) = var('a,l,x') solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params (a,l,x) = var('a,l,x') a=24 l=1.28 solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the eqution by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x) the solve() function give me the roots well.

Thanks for help.

5
None

updated 2020-11-21 16:27:01 +0100

solve result contain variable which to solved

Hi!

I'm newbie with ~~sageplease~~ sage please help me what I doing wrong!

I do: (a,l,x) = var('a,l,x') solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params (a,l,x) = var('a,l,x') a=24 l=1.28 solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the eqution by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x) the solve() function give me the roots well.

Thanks for help.

6
None

updated 2020-11-21 16:27:57 +0100

solve result contain variable which to solved

Hi!

I'm newbie with ~~sage~~ Sage please help me what I I'm doing wrong!

I do: (a,l,x) = var('a,l,x') solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params (a,l,x) = var('a,l,x') a=24 l=1.28 solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the eqution by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x) the solve() function give me the roots well.

Thanks for help.

7
None

updated 2020-11-21 16:28:58 +0100

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I ~~do:~~ do:

(a,l,x) = ~~var('a,l,x')~~ var('a,l,x')

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params
~~(a,l,x) = var('a,l,x') a=24 l=1.28~~
a=24

l=1.28

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the eqution by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x) the solve() function give me the roots well.

Thanks for help.

8
None

updated 2020-11-21 16:29:57 +0100

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I do:

(a,l,x) = var('a,l,x')

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params

a=24

l=1.28

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the ~~eqution~~ equation by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x) the solve() function give me the roots well.

Thanks for help.

9
None

updated 2020-11-21 16:30:17 +0100

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I do:

(a,l,x) = var('a,l,x')

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params

a=24

l=1.28

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the equation by hand into the form below: solve(sqrt(x^4-2x^3+2x^2-2~~x+1)-(2a/l),x)~~ x+1)-(2*a/l),x)

the solve() function give me the roots ~~well.~~well.*

Thanks for help.

10
None

updated 2020-11-21 16:30:46 +0100

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I do:

(a,l,x) = var('a,l,x')

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params

a=24

l=1.28

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

~~Remark:~~ *Remark: Already I found that if I reorder the equation by hand into the form ~~below:~~ below:

solve(sqrt(x^4-2x^3+2~~x^3+2~~x^2-2~~x^2-2~~x+1)-(2~~x+1)-(2*a/l),x)~~a/l),x)

the solve() function give me the roots well.*

Thanks for help.

11
None

updated 2020-11-21 16:31:41 +0100

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I do:

(a,l,x) = var('a,l,x')

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params

a=24

l=1.28

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

*Remark: Remark: Already I found that if I reorder the equation by hand into the form below:

solve(sqrt(x^4-2x^3+2~~x^3+2~~x^2-2~~x^2-2~~x+1)-(2~~x+1)-(2~~a/l),x)~~a/l),x)~~

the solve() function give me the roots well.*well.

Thanks for help.

12
None

updated 2020-11-21 16:39:53 +0100

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I do:

(a,l,x) = var('a,l,x')

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params

a=24

l=1.28

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

Remark: Already I found that if I reorder the equation by hand into the form below:

solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x)

the solve() function give me the roots well.

But I still not understand the problem with the first form.

Thanks for help.

13
None

updated 2020-11-21 16:50:54 +0100

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I do:

(a,l,x) = var('a,l,x')

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == (sqrt(x^2 + 1)a + 2l)/(sqrt(x^2 + 1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params

a=24

l=1.28

solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x)

--> [x == 1/75(75sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]

So result still contain x itself... I'm confused about it.

~~Remark: Already I found that if I reorder the equation by hand into the form below:~~

solve(sqrt(x^4-2x^3+2x^2-2x+1)-(2a/l),x)

the solve() function give me the roots well.

But I still not understand the problem with the first form.

Thanks for help.

14
None

updated 2020-11-22 11:27:10 +0100

tmonteil
27413 ●31 ●204 ●517 http://wiki.sagemath.o...

solve result contain variable which to solved

Hi!

I'm newbie with Sage please help me what I'm doing wrong!

I do:

(a,l,x) = var('a,l,x')var('a,l,x') solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x) solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x) --> [x == (sqrt(x^2 + 1)a 1)*a + 2l)/(sqrt(x^2 2*l)/(sqrt(x^2 + 1)*a)]1)*a)]

Why x result contain x itself!? It's not ture for any x.

If I set a,l params
~~a=24~~
a=24 l=1.28 l=1.28solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x) solve(1/(a*(x-1))==(sqrt(x^2+1^2)/2/l),x) --> [x == 1/75(75sqrt(x^2 1/75*(75*sqrt(x^2 + 1) + 8)/sqrt(x^2 + 1)]1)]

So result still contain x itself... I'm confused about it.

Thanks for help.