Hello,
if you have an expression like
y=function("y")(x)
f=diff(y,x)+5*y
and would like replace y by x^2,
I would normally call
f.subs(y==x^2).show()
But this only substitutes the y in the second term, but not the function y in the derivative. So, in order to do that I do
f.subs(y==x^2).subs(diff(y,x)==diff(x^2,x)).show()
This works and I can live with this, but I was wondering if there is a "short cut" to replace the function y in the second term as well as the function y in the derivative at the same time?
I am looking for something similar to
(D[y[x],x]+5y[x])/.y->Function[x,x^2]
in Mathematica.
