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Here is a box with a curve in it

ppplot=polygon([( 0 , 0 ), ( 0 , 10 ), ( 1 , 10 ),( 1 , 0 )], color = "#bbd2e1")
ppplot+=plot(1/x,(x, 0.1, 1), color="red")
ppplot+=plot(-10*x+10,(x, 0, 1), color="green",linestyle="--")
ppplot+=line([(0, 10), (1,10),(1,0)], color="green",linestyle="--")
ppplot+=circle((1,10), .1,edgecolor="green",fill=true, facecolor="green")
show(ppplot,aspect_ratio=0.05)

I have two questions :

1) how to impeach that the aspect-ratio be applied to circle() 2) how to obtain a new curve where $1/x$ but this time with the origin of the axes in the green dot (symetry by the dashed line.

Here is a box with a curve in it

ppplot=polygon([( 0 , 0 ), ( 0 , 10 ), ( 1 , 10 ),( 1 , 0 )], color = "#bbd2e1")
ppplot+=plot(1/x,(x, 0.1, 1), color="red")
ppplot+=plot(-10*x+10,(x, 0, 1), color="green",linestyle="--")
ppplot+=line([(0, 10), (1,10),(1,0)], color="green",linestyle="--")
ppplot+=circle((1,10), .1,edgecolor="green",fill=true, facecolor="green")
show(ppplot,aspect_ratio=0.05)

I have two questions :

1) how to impeach that the aspect-ratio be applied to circle() circle()

2) how to obtain a new curve where $1/x$ but this time with the origin of the axes in the green dot (symetry by the dashed line. line.

3) In the same way how to change the normal cartesian representation of a function from (x,y) to (y,x) in plot