b=4*3^(2*x-1)==5*4^(x+2)
show(b)
solve(b,x)
The Solution is:
[4^(x + 2) == 4/5*3^(2*x - 1)]
Should the solve alg. solve for x?
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b=4*3^(2*x-1)==5*4^(x+2)
show(b)
solve(b,x)
The Solution is:
[4^(x + 2) == 4/5*3^(2*x - 1)]
Should the solve alg. solve for x?
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