Why this command doesn't give me any solution :
solve([2*x+y==0,x-2*y==1],x)
I suppose because, there is an unique solution and x doesn't depend on y.
Now I would like to know when we solve an equation such that $$f(z)= 0\iff Re(x)+iIm(x)=0 $$ with $z=x+iy$ and $f(z)=5z-i\overline{z}^2+3+2i$
real(x)=-2*x*y + 5*x + 3
im(x) = -x^2 + y^2 + 5*y + 2
solve([real(x)==0, im(x)==0], x)
Is this command the right one to solve this problem ?
