I formed my matrix A from, A = random_matrix(QQ, 6, algorithm='echelonizable', rank=6, upper_bound=9), I then changed the ring to RDF (A.change_ring(RDF)) , I further obtain my SVD matrix (U, S, V = B.SVD()). How do i find the inverse of A using SVD
![]() | 1 | initial version |
I formed my matrix A from, A = random_matrix(QQ, 6, algorithm='echelonizable', rank=6, upper_bound=9), I then changed the ring to RDF (A.change_ring(RDF)) , I further obtain my SVD matrix (U, S, V = B.SVD()). How do i find the inverse of A using SVD
![]() | 2 | None |
I formed my matrix A A from, A = random_matrix(QQ, 6, algorithm='echelonizable', rank=6,
, I then changed the ring to RDF upper_bound=9), upper_bound=9)(A.change_ring(RDF)) (A.change_ring(RDF)
) , I further obtain my SVD matrix (U, (U,
S, V =
). How do i find the inverse of A using SVDB.SVD()). B.SVD()