sage: floor(sqrt(2)*sqrt(2.)/2)==1
true
sage: (sqrt(2.)*sqrt(2.)/2)==1.0
false
sage: (sqrt(2.)*sqrt(2.)/2)
1.00000000000000 sage :((2^(1/2.))== sqrt(2.))
true
sage: (((2.^(1/2))* sqrt(2.)) == 2.)
false
why it happen about approximate????
Revision history [back]
 | 1 | initial version |
how is precision in sage?
| | 2 | No.2 Revision |
how is precision Rounding error in sage?sqrt(2) in Sage
sage: floor(sqrt(2)*sqrt(2.)/2)==1In the following code,
true
sage: (sqrt(2.)*sqrt(2.)/2)==1.0 false
floor(sqrt(2)*sqrt(2.)/2)==1
True
sage: (sqrt(2.)*sqrt(2.)/2)
(sqrt(2.)*sqrt(2.)/2)==1.0
False
sage: (sqrt(2.)*sqrt(2.)/2)
1.00000000000000
sage :((2^(1/2.))== sqrt(2.))
true
sqrt(2.))
True
sage: (((2.^(1/2))* sqrt(2.)) == 2.)
false
2.)
Falsewhy it happen about approximate????is there an approximation error?
