Is there an alternative way to calculate this improper integral?
integral(log(x)/(x^2 - 1),x,0,infinity)
the integral is convergent to pi^2/4 but Sage says divergent.
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Is there an alternative way to calculate this improper integral?
integral(log(x)/(x^2 - 1),x,0,infinity)
the integral is convergent to pi^2/4 but Sage says divergent.
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