Ask Your Question
0

what is "set_verbose"command in buchberger algorithm?

asked 2013-04-05 11:35:32 +0200

Neda gravatar image

updated 2013-04-05 13:33:31 +0200

fidbc gravatar image

Hello I computed buchberger algorithm as

R.<x,y,z>=PolynomialRing(QQ,3)
I=ideal(x^6-y^2+z, z^3+y^2)
set_verbose(3)
I.groebner_basis('toy:buchberger')
(x^6 - y^2 + z, z^3 + y^2) => 0
G: set([x^6 - y^2 + z, z^3 + y^2])

(z^3 + y^2, x^6 - y^2 + z) => 0
G: set([x^6 - y^2 + z, z^3 + y^2])

2 reductions to zero.

[x^6 - y^2 + z, z^3 + y^2]

I just want to know what is set_verbose(3) command for in this? also toy: ... thank you

edit retag flag offensive close merge delete

1 Answer

Sort by ยป oldest newest most voted
1

answered 2013-04-05 13:38:46 +0200

fidbc gravatar image

As the name suggests set_verbose is used to change the verbosity level. Try running the code without using the call set_verbose(3) to see the difference in the output.

Related link: set_verbose.

For your second question, you can check the manual.

edit flag offensive delete link more

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2013-04-05 11:35:32 +0200

Seen: 364 times

Last updated: Apr 05 '13