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Intersection of a Cube with two planes and resulting polyhedron

asked 2013-02-18 17:21:51 -0500

assadabbasi gravatar image

updated 2013-02-18 22:31:10 -0500

ppurka gravatar image

Hi,

I am new to sage and trying to solve a problem where I have two planes cutting a cube. How can I find the resulting polytope/polyhedron as a result of this cut.

cube = polytopes.n_cube(3)
cube.Hrepresentation()

plane1 = Polyhedron(eqns=[(0,1,0,0)])
plane2 = Polyhedron(eqns=[(1,0,0,-1)])

Please also tell me that what is meant by eqns=[(0,1,0,0)] in sage? what equality it represent? similarly eqns=[(1,0,0,-1)] ?

Thanks

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The last example in the documentation might be useful to understand what `eqns` means. http://x0.no/apde

fidbc gravatar imagefidbc ( 2013-02-19 02:49:11 -0500 )edit

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answered 2013-02-19 10:03:01 -0500

twch gravatar image

For an answer of the interpretation of eqns see your first post.

in order to calculate the intersection of your two planes and the cube, you can simply put all conditions in a new Polyhedron

cube = polytopes.n_cube(3)
plane1 = Polyhedron(eqns=[(0,1,0,0)])
plane2 = Polyhedron(eqns=[(1,0,0,-1)])
intersec=Polyhedron(eqns=plane1.equations()+plane2.equations(), ieqs=cube.inequalities())
print intersec.Hrepresentation()
intersec.show()
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answered 2013-02-20 11:01:10 -0500

assadabbasi gravatar image

Thank you very much. Your explanation was very useful in solving my problem.

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Asked: 2013-02-18 17:21:51 -0500

Seen: 539 times

Last updated: Feb 20 '13