I am looking for one-dimension subspace x such that for every v∈⟨x⟩ we have v.v=0.
I try this:
V = VectorSpace(GF(5),2)
for i in V.subspaces(1):
for x in i:
if (x*x==0):
print(i)but I have trouble with it:
sage gives me subspace "Vector space of degree 2 and dimension 1 over Finite Field of size 5 Basis matrix: [1 0]" this subspace is not satisfied my condition
You need to take care of the zero element of the subspace. for x in i will iterate over all the vectors including the zero vector.
how can I take care of the zero element?
If the subspaces are not too big, you can do for x in i[1:]: # rest of your code If the subspaces are big, then doing `i[1:]` will take time and memory. In this case, change your if condition if x != i.zero_vector() and x*x == 0: # rest of your code.
Asked: 12 years ago
Seen: 340 times
Last updated: Feb 05 '13
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