Dealing with 'NaN' values in lists

293 ●17 ●32 ●40

Hello!

Maybe somebody here has an experience on working with 'NaN' values in Sage.

My situation is the following: I need to load some experimentally measured data into a list of float values. But unfortunately, the experimental data set is not "solid" - it has 'NaN' values somewhere inside.

What I currently need to perform first of all is to calculate the average value of a list slice. Preferably, simply using 'mean()' if it is possible.

So could somebody please give me an advice how to work with such arrays correctly?

Thank you.

answered 12 years ago

vdelecroix
7640 ●20 ●85 ●168 http://www.labri.fr/pe...

updated 12 years ago

Hello,

You should remove the values NaN from your list and then use mean. It is a bit tricky, because of the following behavior

sage: float(NaN) == float(NaN)
False

The answer may be found here. I reproduce what you want in your case

sage: l = [float(NaN), float(0.01), float(19), float(-3), float(NaN)]
sage: from math import isnan
sage: clean_list = [x for x in l if not isnan(x)]
sage: print clean_list
[0.01, 19.0, -3.0]
sage: mean(clean_list)
5.336666666666667

Vincent

link

Comments

Hello! Thank you for reply! I tried to use 'is NaN' as you suggested, but the problem is that I need to obtain the data from a text file. But when I use float('NaN'), I get the 'float' type, naturally. Whereas type(NaN) gives me <type 'sage.symbolic.expression.expression'=""> which is different. So I cannot use 'is NaN' construction for the floats obtained by parsing the text file.

v_2e ( 12 years ago )

I adapt my answer to your problem...

vdelecroix ( 12 years ago )

Thanks! It works! It's a pity I have to check and remove every item in my lists. It may be rather time-consuming with large data sets. Anyway, thank you for the recipe!

v_2e ( 12 years ago )

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