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Working with series

asked 12 years ago

yrogirg gravatar image

updated 12 years ago

I can't get how to work with series. I do

sage: R.<t> = PowerSeriesRing(QQ)
sage: t^2
t^2
sage: sin(t)

but the last rises an error. I want to do usual manipulations like sin(t)/cos(t+2)^2.

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What do you mean by sin(t)? Do you want the Taylor series for sin around some point?

niles gravatar imageniles ( 12 years ago )

yes, generally Puiseux series would be better, but sin t is to return Taylor expansion around zero if it doesn't specified in it's type directly.

yrogirg gravatar imageyrogirg ( 12 years ago )

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answered 12 years ago

niles gravatar image

Use the taylor method to get a Taylor polynomial. This needs to be done in the symbolic ring since the power series ring is purely algebraic and doesn't know about derivatives.

sage: t = var('t')
sage: f = sin(t)
sage: s_poly = f.taylor(t,0,7)
sage: s_poly
-1/5040*t^7 + 1/120*t^5 - 1/6*t^3 + t
sage: s_poly.parent()
Symbolic Ring

The power_series method will convert the Taylor polynomial to a power series for you:

sage: s_ser = s_poly.power_series(QQ)
sage: s_ser
t - 1/6*t^3 + 1/120*t^5 - 1/5040*t^7 + O(t^8)
sage: s_ser.parent()
Power Series Ring in t over Rational Field

sage: g = cos(t)
sage: c_poly = g.taylor(t,0,7)
sage: c_poly
-1/720*t^6 + 1/24*t^4 - 1/2*t^2 + 1
sage: c_ser = c_poly.power_series(QQ)
sage: c_ser
1 - 1/2*t^2 + 1/24*t^4 - 1/720*t^6 + O(t^7)

Over the power series ring, you can do arithmetic with the power series. Note that you will need to change "t" from the generator of the symbolic ring to the generator of the power series ring in order to use things like t+2:

sage: t.parent()
Symbolic Ring

sage: t = s_ser.parent().gen()
sage: t.parent()
Power Series Ring in t over Rational Field

sage: s_ser/c_ser(t+2)
-45/19*t + 1890/361*t^2 - 83085/6859*t^3 + 3677670/130321*t^4 - 649441779/9904396*t^5 + 7173329982/47045881*t^6 - 17745663554041/50056817384*t^7 + O(t^8)
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Asked: 12 years ago

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Last updated: Jun 02 '12