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contour plot not working as expected

asked 2012-05-06 21:34:12 -0600

sagemb gravatar image

updated 2013-06-03 04:33:31 -0600

tmonteil gravatar image

Hi all,

I am looking at ways to determine the sign of an angle between a reference vector (a,b) and any other vector(x,y) of the plane. To do so, I have decided to use the determinant of the matrix: [[a b],[x y]] which equals ax-by. I wanted then to check that the formula works by displaying the plane area which positive and negative signs using the contour_plot.

Here is my question:

Why is the 3rd graph not showing 2 horizontal areas instead of the vertical displayed?

var('x y')
f(x,y,a,b)=(a*y-b*x)/abs(a*y-b*x)
plota1b1=contour_plot(f(x,y,1,1),(-10,10),(-10,10),cmap='jet',colorbar=true)
plota0b1=contour_plot(f(x,y,0,1),(-10,10),(-10,10),cmap='jet',colorbar=true)
plota1b0=contour_plot(f(x,y,1,0),(-10,10),(-10,10),cmap='jet',colorbar=true)
show(plota1b1)
show(plota0b1)
show(plota1b0)

Thanks

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answered 2012-05-07 03:32:36 -0600

Jason Grout gravatar image

The problem is the way you are calling contour plot. Notice that f(x,y,1,0) is y/abs(y). When you are calling contour plot, you aren't specifying which range goes with which variable, so it assumes that the first numeric range (the horizontal axis) goes with the first variable in the expression, which is y.

The solution is to specify explicitly that the horizontal axis corresponds with the x variable, and the vertical axis is for the y variable:

plota1b0=contour_plot(f(x,y,1,0),(x,-10,10),(y,-10,10),cmap='jet',colorbar=true)

See a live example

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answered 2012-05-07 03:43:17 -0600

sagemb gravatar image

Oh, I see. Thank you very much!

BR M

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Comments

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Go ahead and check that as an answer if you feel like it answers your question.

Jason Grout gravatar imageJason Grout ( 2012-05-07 12:48:14 -0600 )edit

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Asked: 2012-05-06 21:34:12 -0600

Seen: 154 times

Last updated: May 07 '12