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What file does the "in" operator reside in?

asked 2011-11-16 18:27:19 -0500

process91 gravatar image

When I run something like

sage: 32 in ZZ

Where is this "in" operator defined? In general, is there a nice way to trace something like this to find the file(s) being accessed?

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answered 2011-11-16 23:17:24 -0500

Mike Hansen gravatar image

The in operator uses the Python special method __contains__. The Python documentation about this is here. You can get the source code for this by doing ZZ.__contains__??.

There is the trace function, but it isn't very useful for code in (compiled) Cython files unless you turn on profiling for Cython.

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Thanks, is there any way to tell from the ?? output what file it is being defined in (as most other commands show)? As is, I grepped the files in the sage devel directory and came up with structure/parent.pyx and structure/parent.c files. Incidentally, should I be modifying pyx files or only their c counterparts?

process91 gravatar imageprocess91 ( 2011-11-17 05:21:17 -0500 )edit

answered 2011-11-17 07:25:21 -0500

parzan gravatar image

updated 2011-11-17 07:29:58 -0500

You can find the function source like this:

sage: ZZ.__contains__.__doc__
'File: sage/structure/parent.pyx (starting at line 950)...

and what object it belongs to with ZZ.__contains__.__objclass__ (and then you can do ZZ.__contains__.__objclass__??). I don't know if this will work generally.

Also, here are listed many operators with their corresponding names.

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Thanks very much, that's very useful.

process91 gravatar imageprocess91 ( 2011-11-17 08:21:02 -0500 )edit

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Asked: 2011-11-16 18:27:19 -0500

Seen: 123 times

Last updated: Nov 17 '11