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evaluating an expression

asked 2011-11-13 23:59:50 -0500

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started to use open source mathematical software. And i have some questions since i can not find in google what i am searching for (maybe i am a bad searcher :S).

The thing is if i write in maple (with predefined F, M, q and Q):

Sum('F[ix]', 'i' = 1 .. n) = 0; '-2*F*cos(45*deg)-3*Q+4*RB*cos(45*deg)-RB*sin(45*deg)-M = 0'; evalf[4](solve(%, RB))

I get

RB := 19.51

And in Sage:


i get:

[23/3*sqrt(2) + 26/3 == 23/3*sqrt(2) + 26/3]

Now i do not find any equivalent to evalf in sage. Could someone help me, please?

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answered 2011-11-14 02:53:09 -0500

DSM gravatar image

Hi! I think you must have assigned one too many of your variables (like assigning a value to RB) to come up with your last expression. Also, I don't see what predefined, lowercase q you're referring to.

In any case, here's roughly what I'd do. First, define the variables and the equation, and then solve it:

sage: var("F, Q, M, RB")
(F, Q, M, RB)
sage: deg = pi/180;
sage: eq = -2*F*cos(45*deg)-3*Q+4*RB*cos(45*deg)-RB*sin(45*deg)-M == 0
sage: eq
-sqrt(2)*F + 3/2*sqrt(2)*RB - M - 3*Q == 0
sage: solve(eq,RB)
[RB == 1/3*sqrt(2)*M + sqrt(2)*Q + 2/3*F]
sage: for sol in solve(eq,RB):
....:         print sol.rhs()
1/3*sqrt(2)*M + sqrt(2)*Q + 2/3*F

Then solve it. By default, solve returns a list of equations, so you can loop over them like I did or index into them using [0], [1], [2], etc. I prefer the solution_dict style:

sage: solve(eq,RB, solution_dict=True)
[{RB: 1/3*sqrt(2)*M + sqrt(2)*Q + 2/3*F}]
sage: sols = solve(eq,RB, solution_dict=True)
sage: sols[0][RB]
1/3*sqrt(2)*M + sqrt(2)*Q + 2/3*F

in which you get a list of dictionaries, with each dictionary corresponding to a possible solution, and then you simply use the variable name as the index. We can then extract a solution:

sage: rb = sols[0][RB]
sage: rbval = rb.subs(M=23, Q=6, F=1/4)
sage: rbval
41/3*sqrt(2) + 1/6

and I've substituted some basically random M, Q, and F values into it. This can then be evaluated numerically (the evalf equivalent) by using the numerical_approx method:

sage: rbval.n()
sage: rbval.numerical_approx()
sage: rbval.n(100)

There are lots of ways to turn a symbolic expression into a "number", though. See my answer to this question on a similar subject.

Does that make sense?

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Asked: 2011-11-13 23:59:50 -0500

Seen: 2,719 times

Last updated: Nov 14 '11