Hi, I'm very very new in Sage. I have a problem trying this:
x=var('x')
f=10*(1-exp(-0.23*(x)))^2
g=20*(1-exp(0.23*(x-14)))^2-10
I'm want to get the intersection point(s). From Maple, I know there is three, but when I try to solve for x:
solve(f==g,x)
[ ]
Sage gives me that [ ]! What does it mean? Thanks in advance
Just putting this in standard syntax:
sage: f = 10*(1-exp(-.23*x))^2
sage: g = 20*(1-exp(-.23*(x-14)))^2-10
sage: g
20*(e^(-0.230000000000000*x + 3.22000000000000) - 1)^2 - 10
sage: f
10*(e^(-0.230000000000000*x) - 1)^2
sage: solve(f==g,x)
[]
Sage gives solutions in list form by default. Python (which Sage is largely based upon) lists are in square brackets. This one has no items, so it is the empty list.
sage: solve(f==g,x,to_poly_solve=True) # invokes another type of solver, but one which doesn't always return exact answers
[]
But there is another issue, which is that solve (which is from Maxima's solve) seeks exact solutions, in general. If it can't solve it exactly, it may indeed return no answers, even if there are some.
Now, a little playing with find_root discovers something interesting.
sage: f.subs(x=1000)
10.0000000000000
sage: g.subs(x=1000)
10.0000000000000
Well, maybe Maxima's solve capabilities should have found that... but apparently it didn't. However, you may find find_root is what you are actually interested in.
sage: find_root(f-g,0,20)
11.070582936901683
My apologies kcrisman, you were right. Maple solves it numerically too. I had to use find_root, that was the correct way. Maple has some advantages manipulating symbols, but I choose Sage. Thanks for your help.
Bye bye.
Thank you for spend your time answering my question. Finally I used Maple in the solving of my problem. Greetings.
Asked: 2011-10-27 23:19:28 +0100
Seen: 1,820 times
Last updated: Oct 29 '11
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.
