The solution you get does not evaluate the integrals, which are held expressins. The simplest way to force their evaluation is :
sage: solution.unhold()
Warning: piecewise indefinite integration does not return a continuous antiderivative
Warning: piecewise indefinite integration does not return a continuous antiderivative
1/36*(9*(2*t*e^(2*t) - 5*e^6 - e^(2*t))*e^t*heaviside(t - 3) - 4*(3*t*e^(3*t) - 8*e^9 - e^(3*t))*heaviside(t - 3))*e^(-3*t) + 6*e^(-2*t) - 4*e^(-3*t)
$$\frac{1}{36} \, {\left(9 \, {\left(2 \, t e^{\left(2 \, t\right)} - 5 \, e^{6} - e^{\left(2 \, t\right)}\right)} e^{t} H\left(t - 3\right) - 4 \, {\left(3 \, t e^{\left(3 \, t\right)} - 8 \, e^{9} - e^{\left(3 \, t\right)}\right)} H\left(t - 3\right)\right)} e^{\left(-3 \, t\right)} + 6 \, e^{\left(-2 \, t\right)} - 4 \, e^{\left(-3 \, t\right)}$$
Thi works if and only if Sage is able to get a closed form of your integrals ; otherwise, it will return the held form...
Another way to force these evaluations is to evaluate the string representation of your representation :
sage: eval(preparse(repr(solution)))
Warning: piecewise indefinite integration does not return a continuous antiderivative
Warning: piecewise indefinite integration does not return a continuous antiderivative
1/36*(9*(2*t*e^(2*t) - 5*e^6 - e^(2*t))*e^t*heaviside(t - 3) - 4*(3*t*e^(3*t) - 8*e^9 - e^(3*t))*heaviside(t - 3))*e^(-3*t) + 6*e^(-2*t) - 4*e^(-3*t)
$$\frac{1}{36} \, {\left(9 \, {\left(2 \, t e^{\left(2 \, t\right)} - 5 \, e^{6} - e^{\left(2 \, t\right)}\right)} e^{t} H\left(t - 3\right) - 4 \, {\left(3 \, t e^{\left(3 \, t\right)} - 8 \, e^{9} - e^{\left(3 \, t\right)}\right)} H\left(t - 3\right)\right)} e^{\left(-3 \, t\right)} + 6 \, e^{\left(-2 \, t\right)} - 4 \, e^{\left(-3 \, t\right)}$$
In that specific case, you may also convert it to sympy, where the doit() method allows for such a re-evaluation :
sage: solution._sympy_().doit()._sage_()
1/36*(9*(2*t*e^(2*t) - 5*e^6 - e^(2*t))*e^t*heaviside(t - 3) - 4*(3*t*e^(3*t) - 8*e^9 - e^(3*t))*heaviside(t - 3))*e^(-3*t) + 6*e^(-2*t) - 4*e^(-3*t)
$$\frac{1}{36} \, {\left(9 \, {\left(2 \, t e^{\left(2 \, t\right)} - 5 \, e^{6} - e^{\left(2 \, t\right)}\right)} e^{t} H\left(t - 3\right) - 4 \, {\left(3 \, t e^{\left(3 \, t\right)} - 8 \, e^{9} - e^{\left(3 \, t\right)}\right)} H\left(t - 3\right)\right)} e^{\left(-3 \, t\right)} + 6 \, e^{\left(-2 \, t\right)} - 4 \, e^{\left(-3 \, t\right)}$$
BTW :
sage: import sympy
sage: sympy.dsolve(equation._sympy_())._sage_()
y(t) == -1/4*(5*e^6*heaviside(t - 3) - 4*C1)*e^(-2*t) + 1/9*(8*e^9*heaviside(t - 3) + 9*C2)*e^(-3*t) + 1/6*t*heaviside(t - 3) - 5/36*heaviside(t - 3)
$$y\left(t\right) = -\frac{1}{4} \, {\left(5 \, e^{6} H\left(t - 3\right) - 4 \, C_{1}\right)} e^{\left(-2 \, t\right)} + \frac{1}{9} \, {\left(8 \, e^{9} H\left(t - 3\right) + 9 \, C_{2}\right)} e^{\left(-3 \, t\right)} + \frac{1}{6} \, t H\left(t - 3\right) - \frac{5}{36} \, H\left(t - 3\right)$$
(Converting the boundary condituions to sympy is a tad intricate...).
Such conversions to other CAS may be helpful if this CAS is able to gett a closed form of these integral. But that may entail further work to convert these closed forms back to Sage :
sage: solution._mathematica_().sage(locals={"HeavisideTheta":heaviside})
1/36*(9*((2*t - 1)*e^(2*t) - 5*e^6)*e^t*heaviside(t - 3) - 4*((3*t - 1)*e^(3*t) - 8*e^9)*heaviside(t - 3))*e^(-3*t) + 6*e^(-2*t) - 4*e^(-3*t)
$$\frac{1}{36} \, {\left(9 \, {\left({\left(2 \, t - 1\right)} e^{\left(2 \, t\right)} - 5 \, e^{6}\right)} e^{t} H\left(t - 3\right) - 4 \, {\left({\left(3 \, t - 1\right)} e^{\left(3 \, t\right)} - 8 \, e^{9}\right)} H\left(t - 3\right)\right)} e^{\left(-3 \, t\right)} + 6 \, e^{\left(-2 \, t\right)} - 4 \, e^{\left(-3 \, t\right)}$$
HTH,
