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Graphing derivatives of implicitly given functions

asked 2011-01-29 17:10:11 +0200

Sorry if this is too elementary.

I want to graph the derivative of a function y that is given implicitly as a function of x. I would appreciate any suggestions.

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answered 2011-01-29 22:10:27 +0200

kcrisman gravatar image

Unfortunately, this is pretty hard to do in Sage. Even this attempt (eventually) fails:

sage: y = function('y',x)
sage: f = y*x==1; f
x*y(x) == 1
sage: f.derivative(x)
x*D[0](y)(x) + y(x) == 0
sage: g = f.derivative(x)
sage: g.operands()[0].operands()[0].operands()[1]
sage: h = g.solve(g.operands()[0].operands()[0].operands()[1])[0]; h
D[0](y)(x) == -y(x)/x
sage: implicit_plot(h.rhs(),(x,-1,1),(y,-1,1))

I don't know that this is easy to fix in general, either, because of course derivatives in implicit functions can be arbitrarily complicated to solve for, and so not necessarily accessible to a computer method. I don't think there are any numerical methods for doing this.

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answered 2011-01-30 13:58:03 +0200

niles gravatar image

Surely there is a way to do this numerically, isn't there? What I mean is that one should be able to write a function which, for a given numerical value of x, solves the implicit equation to find the value of the derivative at x -- using find_root, perhaps. And then one ought to be able to plot this function.

Of course this won't work for every implicitly defined function, but sage's numerics should work for a lot of cases that users actually want.

But I don't know enough about sage symbolics to actually do this. Any takers?

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answered 2011-02-03 10:13:06 +0200

mmarco gravatar image

updated 2011-02-03 10:27:46 +0200

You can try this:


This way you avoid the "solve" issue.

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answered 2011-01-29 17:52:21 +0200

Shashank gravatar image

I am not sure whether this is what you are looking for

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Asked: 2011-01-29 17:10:11 +0200

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Last updated: Feb 03 '11