I want to come up with a function that will return true when I compare (x−1)2+C and x2−2x+C where C is an arbitrary constant. Any way that you know can do this ?
So you want to know if a specific mathematical expression (like (x−1)2−(x2−2x)) is a constant. Just check whether its derivative is zero:
sage: var('C, C2')
sage: diff(((x-1)^2+C) - (x^2-2*x+C2), x)
0
sage: bool(diff(((x-1)^2+C) - (x^2-2*x+C2), x) == 0)
TrueThere is no such function, because they're not equal. Perhaps the second expression should be x^2-2x+1+C...
What have you tried? Here are two options:
sage: var('C')
sage: expand(((x-1)^2+C) - (x^2-2*x+1+C))
0
sage: bool(expand((x-1)^2+C) == expand(x^2-2*x+1+C))
TrueI know there is none. But I want to make one if possible at all. Probably you will like the expression with different "C"
(x−1)2+C1 and x2−2x+C2
For any value of C1 there is a value of C2 that makes the two equations equal. Anyone else have any idea?
one can find indefinite integral of sin(x)cos(x) as (1/2)*(sin(x))^2+C_1 or -(1/2)*(cos(x))^2+C_2 both are right. But can I make a function using sage methods that will consider both as same?
hey you can put math between dollar signs and it'll typeset
will do next time. thanks for letting me know.
you can edit your previous posts too :)
I was able to edit the answer, but do not see any edit button for comments.
Asked: 14 years ago
Seen: 3,088 times
Last updated: Nov 17 '10
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