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Variable range()

asked 2010-10-16 15:57:24 +0100

Lynda gravatar image

Hello, I have the following code:

def f(a,b,c,x):
    xtemp=a
    for i in range(b,x):
        xtemp=xtemp-xtemp*c
    return xtemp   
var('t')
plot(f(10000000,1,0.01,t),3,20)

and got the error

TypeError: range() integer end argument expected, got
sage.symbolic.expression.Expression.

I understand that range does nor support 'var' object, but how can I have a variable range in this kind of function?

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Thank you Niles it works well for my needs

Lynda gravatar imageLynda ( 2010-10-17 15:39:14 +0100 )edit

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answered 2010-10-16 16:10:10 +0100

niles gravatar image

A lambda function might be the quickest workaround:

plot(lambda t: f(10000000,1,0.01,t),3,20)

And if you don't want to get the deprecation warning about range not taking float inputs, you could modify your function to:

def f(a,b,c,x):
    xtemp=a
    for i in range(b,ceil(x)):
        xtemp=xtemp-xtemp*c
    return xtemp
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Asked: 2010-10-16 15:57:24 +0100

Seen: 859 times

Last updated: Oct 16 '10