Power series with alternating exponent

asked 2023-07-09 16:44:53 +0100

515 ●9 ●20 ●37

updated 2023-07-09 22:59:25 +0100

Mathematically, we have $4^{(-1)^k} = \frac18 (17+15(-1)^k)$ for all integers $k$. However, this identity is not being used for the computation of $\sum_{k=0}^\infty 4^{(-1)^k} x^k$:

sage: sum(4^((-1)^k)*x^k, k, 0, oo)._giac_().normal().sage()
sum(4^((-1)^k)*x^k, k, 0, +Infinity)

However:

sage: sum(1/8*(17+15*(-1)^k)*x^k, k, 0, oo)._giac_().normal().sage()
-1/4*(x + 16)/(x^2 - 1)

Is there a way to compute the first expression with Sage or is it possible to implement this process so that Sage can handle such expressions automatically?

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answered 2023-07-09 21:19:38 +0100

achrzesz
2768 ●5 ●25 ●60

updated 2023-07-10 13:33:14 +0100

One way is:

var('k')
assume(x>-1)
assume(x<1)
(4*sum(x^(2*k), k, 0, oo)+sum(x^(2*k+1), k, 0, oo)/4).combine()

-1/4*(x + 16)/(x^2 - 1)

A more automatic version:

var('x k')
assume(k,'integer')
w(k)=4^((-1)^k)*x^k
a(k)=w(k=2*k).full_simplify()
b(k)=w(k=2*k+1).full_simplify()
(sum(a(k),k,0,oo)+sum(b(k),k,0,oo)).combine()

-1/4*(x + 16)/(x^2 - 1)

(assuming that both series converge)

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Is there any way Sage can handle $\sum_{k=0}^\infty 4^{(-1)^k} x^k$ directly/automatically?

Thrash ( 2023-07-09 22:57:37 +0100 )edit

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Asked: 2023-07-09 16:44:53 +0100

Seen: 118 times

Last updated: Jul 10 '23

Power series with alternating exponent edit