I know it should be a Python question, but as there is a way to call itertools in Sagemath I ask the question here. According to the documentation
import itertools as it
l1=[1,2,3]
l2=list(it.permutations(l1,2))
l2should work. But in fact it returns an error. To the opposit
import itertools as it
l1=[1,2,3]
l2=list(it.permutations(l1))
l2works correctly. Is it a know problem ?
First off, you don't need itertools here since similar functionality is provides by Sage - try:
list( Permutations(l1,2) )If you insist on using itertools.permutations, it wants the second argument be of standard int type (not Sage's sage.rings.integer.Integer') - this should the job:
list( itertools.permutations(l1,int(2)) )I do not need this particular itertools command but I was intrigued to know how to work with. Now there is a problem. Why am I obliged to use int(2) here and not with other command of the same type ?
I do not know why, but this is what the error produced by itertools tells us about.
Sage has its own class of integers. Some Python tools will gracefully accept Sage integers as input, but not all of them.
Asked: 1 year ago
Seen: 365 times
Last updated: Apr 17 '23
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