convert a lambdified expression to a function

lambdify

asked 2023-01-30 16:08:12 +0200

moon
43 ●8

Hi there, Given an expression f uppon which I have no control (it means that it could be any univariate expression) example:

1/(x + 7) has the type: <class 'sympy.core.power.Pow'>

I need it to be of type function g so that can make some operations on it, therefore lambdified it g = lambdify(x, f) to get type(g)

<function _lambdifygenerated at 0x7fd435c06050> has the type: <class 'function'>

I need this to be a real function therefore, I checked that I can evaluate g, example g(1) This works fine. However if I wanted to calculate let's say the derivative derivative(g,x) then I get a monstruous error:

AttributeError                            Traceback (most recent call last)
Input In [27], in <cell line: 28>()
     24 print(g(Integer(1)))
     25 #print(derivative(g,x)) #This doesn't work too. error: TypeError: unable to convert <function _lambdifygenerated at 0x7fd435d4bb50> to a symbolic expression
     26 #
     27 #method 2: convert f to a function type
---> 28 h = eval(str(f)).function(x)
     29 print(str(h) + " has the type: " + str(type(h)))
     30 print(derivative(h,x))
AttributeError: 'Pow' object has no attribute 'function'

I also tried to do it like this g=eval(f).function(x) with no sucess I am in trouble looking for some help. Thanks in advance M

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Comments

You seem to use Sympy, whereas this site is dedicated to the care and feeding of Sagemath (née Sage).

While Sage incorporates Sympy, use it and can (somewhat awkwardly) use it, your question may be asked on the Sympy list/forum with better chances of getting a significant answer.

HTH,