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Invertible matrix with integer coefficients

asked 2022-12-03 20:43:24 +0200

DreDd gravatar image

I try to build an invertable matrix, but using the .inverse() method returns matrix with rational coefs, so is there an opportunity in sage to return the inverse matrix with integer coefficients by taking out a common factor?

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answered 2022-12-04 00:21:49 +0200

Emmanuel Charpentier gravatar image

Do you mean something like what follows ?

sage: foo=MatrixSpace(ZZ,2).random_element()
sage: while foo.det()==0: foo=MatrixSpace(ZZ,2).random_element()
sage: foo
[-9 -1]
[ 2 -1]
sage: bar=foo.inverse() ; bar
[-1/11  1/11]
[-2/11 -9/11]
sage: gee=gcd(bar.list()) ; gee
1/11
sage: bar/gee
[-1  1]
[-2 -9]

HTH,

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answered 2022-12-03 21:45:55 +0200

FrédéricC gravatar image

Maybe like that

M=matrix(ZZ,2,2,[1,-1,1,0])
M.inverse_of_unit()
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Asked: 2022-12-03 20:43:24 +0200

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Last updated: Dec 04 '22