Group element multiplication in symmetric group

asked 2022-09-21 13:09:01 +0100

vidyarthi
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updated 2024-04-12 11:11:35 +0100

5311 ●4 ●44 ●118

I think this is elementary, but how do we just multiply two elements in the symmetric group. For example, I have a list of elements as

G=SymmetricGroup(5)
A=[(1,2), (1,3,2), (1,4), (1,4)(2,3),(2,4),(2,4,3),(3,4),(2,3,4)]
b=[G(1,5)*G(a) for a in A]
b

When I implement in the above code on the compiler, I get the error 'tuple' object is not callable. Anyway to overcome this error and multiply two elements in the group, or, in any other group? Thanks beforehand.

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answered 2022-09-21 14:24:51 +0100

tmonteil
27423 ●31 ●204 ●517 http://wiki.sagemath.o...

When you define A, the (1,4)(2,3) looks using the tuple (1,4) as a function to be called at (2,3), which explains your error.

If you want A be a list of elements of G you must make it explicit:

sage: A=[G((1,2)), G((1,3,2)), G((1,4)), G([(1,4),(2,3)]),G((2,4)),G((2,4,3)),G((3,4)),G((2,3,4))]

sage: A
[(1,2), (1,3,2), (1,4), (1,4)(2,3), (2,4), (2,4,3), (3,4), (2,3,4)]

Then, you can do:

sage: b=[G((1,5))*a for a in A]
sage: b
[(1,5,2),
 (1,5,3,2),
 (1,5,4),
 (1,5,4)(2,3),
 (1,5)(2,4),
 (1,5)(2,4,3),
 (1,5)(3,4),
 (1,5)(2,3,4)]

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Asked: 2022-09-21 13:09:01 +0100

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Last updated: Sep 21 '22

Group element multiplication in symmetric group edit

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