Automate the code for Topological recursion

asked 2022-06-08 02:19:37 +0100

Anupamsage gravatar image

updated 2023-11-24 13:29:46 +0100

FrédéricC gravatar image

Let me start by giving a brief idea of the recursion. This recursion generate bunch of meromorphic function, and the recursion depend on two variables. Let call the variable $g,n$. Let me state the recursion $$W_{g,n}(z_1, \ldots z_n) = Res_{z=0} \left( W_{g-1, n+1} (z,-z,z_2, \ldots ,z_n)\right) + \sum_{g_1 + g_2 = g} \sum_{n_1 +n_2 = n+1} W_{g_1 , n_1}(z, Part1) W_{g_2 , n_2}(-z, Part2) $$ where Part1 and Part2 are disjoint set whose unioun is ${z_2, \ldots , z_n }$ The recursion is on Euler characteristics, so Euler characteristics on the LHS is $2g -2 +n $ and on the RHS notice that for all the tuples $g^{'} , n^{'}$ , $2g^{'} -2 +n^{'}< 2g -2 +n $.

This is continuation of the post I made, we have few examples of computation here of the above definition. https://ask.sagemath.org/question/626...

var('b,z1,z2,z3');

def y(z):
    return 2*arcsinh( z / (sqrt(2)*b) ) / sqrt(z^2 + 2*b^2)

def K(z):
    return 1 / z / (y(z) - y(-z))

def W02(z1, z2):
    return 1 / (z1 - z2)^2

def W03(z1, z2, z3):
    var('w03')    # use w03 only locally inside this function
    E = ( K(w03) / (w03 - z1) \
          * ( W02(w03, z2) * W02(-w03, z3) +
              W02(w03, z3) * W02(-w03, z2) )
         )
    return E.residue(w03 == 0).canonicalize_radical()

def W11(z1):
    var('w11')    # use w11 only locally inside this function
    E = K(w11) / (w11 - z1) * W02(w11, -w11)
    return E.residue(w11 == 0).canonicalize_radical()

def W12(z1, z2):
    var('w12')    # use w only locally inside this function
    E = ( K(w12) / (w12 - z1) \
          * ( W03(w12, -w12, z2)
              + W02( w12, z2) * W11(-w12)
              + W02(-w12, z2) * W11( w12) )
         )
    return E.residue(w12 == 0).canonicalize_radical()

I want to automatise the above code, so I wrote a pseudo code, if someone can help me to complete it. My code goes as follows

var('b,z1,z2,z3')

def y(z):
    return 2*arcsinh( z / (sqrt(2)*b) ) / sqrt(z^2 + 2*b^2)

def K(z):
    return 1 / z / (y(z) - y(-z))

def W02(0,2,L):
    return 1/(L[0]-L[1])**2

def W(g,n,L):
        z,z1=var('z,z1') 
        P=[var('z_%d' % i) for i in range(2,n+1)]  # Set of variable for {z2, \ldots zn}
        E = 0
        for parts in Partitions(n+1,2):
             for par in SetPartitions(P, 2):
                  E = E + W(g,par[0], par.append(z)) * W(0, par[1].append(-z))

       if g > 0: 
        E = E + W(g-1,n+,L.append(z,-z))

     return (K(z)*E).residue(z == 0).canonicalize_radical()
edit retag flag offensive close merge delete

Comments

1

I did not read in details but W(g,par[0], par.append(z)) cought my eye. Note that par.aapend(z) evaluates to None, while W() seems to expect a list as a third argument. Perhaps, you want par+[z] rather than par.append(z) here.

Max Alekseyev gravatar imageMax Alekseyev ( 2023-11-24 19:31:57 +0100 )edit