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How to symbolic differentiate a sum of N unknown variables?

asked 2 years ago

hanatok gravatar image

updated 2 years ago

I want to take the derivative of the following function with the variable beta:

nk=1βXisinθi1+β2Xi

In maxima, I can do it by:

diff(sum(β*X[i]*sin(θ[i])/(1+β*β*X[i]*X[i]), i, 1, N), β);

How can I do it via sagemath? I have tried the following code:

X = function('X')
theta = function('theta')
var('beta, k, n')
from sage.calculus.calculus import symbolic_sum
E(beta) = symbolic_sum(beta*sin(theta(k))*X(k)/(1+beta*beta*X(k)*X(k)), k, 1, n)
print(E)
print(simplify(derivative(E, beta)))

But the result is different from the one of maxima:

beta |--> beta*sum(X(k)*sin(theta(k))/(beta^2*X(k)^2 + 1), k, 1, n)
beta |--> -2*beta^2*n*X(k)^3*sin(theta(k))/(beta^2*X(k)^2 + 1)^2 + sum(X(k)*sin(theta(k))/(beta^2*X(k)^2 + 1), k, 1, n)

How should I do it correctly?

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This is a known bug: https://trac.sagemath.org/ticket/32161

hanatok gravatar imagehanatok ( 2 years ago )

1 Answer

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answered 2 years ago

Emmanuel Charpentier gravatar image

Workaround :

sage: maxima_calculus.diff(*map(lambda u:u._maxima_(), (E(beta), beta)))._sage_()
-2*beta^2*sum(X(k)^2*sin(theta(k))/(beta^2*X(k) + 1)^2, k, 1, n) + sum(X(k)*sin(theta(k))/(beta^2*X(k) + 1), k, 1, n)

i. e. :

2β2nk=1X(k)2sin(θ(k))(β2X(k)+1)2+nk=1X(k)sin(θ(k))β2X(k)+1

which is, up to the order of the terms, what Maxima returns...

What Sage does :

sage: E(beta).diff(beta)
-(2*beta^2*X(k)^2*sin(theta(k))/(beta^2*X(k) + 1)^2 - X(k)*sin(theta(k))/(beta^2*X(k) + 1))*D[0](sum)(beta*X(k)*sin(theta(k))/(beta^2*X(k) + 1), k, 1, n)

contains D[0](sum)(beta*X(k)*sin(theta(k))/(beta^2*X(k) + 1), which is pure, unadulterated, two-hundred-proof nonsense...

This is a bug and should be reported as such.

HTH,

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Thanks! Your workaround works.

hanatok gravatar imagehanatok ( 2 years ago )

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Asked: 2 years ago

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Last updated: May 27 '22