When I try to solve the following with the assumption z is nonzero solve still outputs the solution with z=0:
assume(z!=0)
solve([x,y*z],x,y,z,solution_dict=True)
Output:
[{x: 0, y: r79, z: 0}, {x: 0, y: 0, z: r80}]
I fixed this by adding an additional variable:
solve([x,y*z,a*z-1],x,y,z,a,solution_dict=True)
Asked: 2022-02-18 04:09:14 +0200
Seen: 165 times
Last updated: Feb 18 '22
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