Create polyhedron for given matrix A and vector b
P(A,b)={x∣ A.x ≤ b}
I have to create a polyhedron with this inputs
but in sage inequalities like this
A.x + b >= 0
, how to convert
1 Answer
$Ax \leq b \iff Ax - b \leq 0 \iff (-A)x + b \geq 0.$
So if you have $(A, b)$ such that $Ax \leq b$ is your polyhedron, then the pair $(A', b)$, where $A'=-A$, is such that $A'x + b \geq 0$ is also your polyhedron.
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Asked: 2021-12-30 19:58:55 +0100
Seen: 374 times
Last updated: Jan 01 '22
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