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number of distinct prime factors of a number

asked 2021-08-16 13:43:50 +0100

aakkbb gravatar image

I know how to write a function that counts the number of distinct prime factors of a number.

Does there exist an inbuilt function for this purpose?

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answered 2021-08-16 16:14:18 +0100

slelievre gravatar image

There is a function to list the prime divisors or prime factors.

It is called prime_divisors, and aliased as prime_factors.

The len function can then give the number of prime factors.

sage: a = 234

sage: prime_divisors(a)
[2, 3, 13]
sage: len(prime_divisors(a))
3

sage: prime_factors(a)
[2, 3, 13]
sage: len(prime_factors(a))
3

The function prime_divisors and its alias prime_factors also exist as methods of integers.

sage: a.prime_divisors()
[2, 3, 13]
sage: len(a.prime_divisors())
3

sage: a.prime_factors()
[2, 3, 13]
sage: len(a.prime_factors())
3
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answered 2021-08-17 14:54:31 +0100

Max Alekseyev gravatar image

Alternatively one can use omega (or bigomega to count prime factors with multiplicity) functions from GP:

sage: gp.omega(234)                                                                                                                                                                                        
3
sage: gp.bigomega(234)                                                                                                                                                                                     
4
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Asked: 2021-08-16 13:43:50 +0100

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Last updated: Aug 17