The following code doesn't work since List[i][j] seems not to be recognized as an integer
cand=["A","B","C","D"]
List=[[],[0,3],[0,1,3],[0]]
L=[[cand(List[i][j]) for j in range(len(i))] for i in range(len(List))]
List[1][1] = 3and its type is integer so I was persuaded that I can call cand(List[1][1]) but i seems that it dosn't work.
Need a little help
There are various problems in your las line:
i is an integer (produced by the range function), so len(i) has no meaningcand is a list so cand(...) has no meaning, instead, you should use cand[...]j should not range over [0,...i-1] but over [0,...List[i]-1]If we fix all the 3 issues, we get:
sage: L=[[cand[List[i][j]] for j in range(len(List[i]))] for i in range(len(List))]
sage: L
[[], ['A', 'D'], ['A', 'B', 'D'], ['A']]
That said, iterating over the elements of a list by looking to its length and calling its items by ranging over its indices is a wrong habit.
It turns out that in Python, the lists are iterable, which means that you can loop directly over elements of a list, which means that if L is a list, you can do: for i in L instead of for j in len(L): i = L[j]
So, if we keep the structure of your loop, by just removing the range noise, we get:
sage: L = [[cand[b] for b in a] for a in List]
sage: L
[[], ['A', 'D'], ['A', 'B', 'D'], ['A']]
As you can see, it is more compact, more readable, and there is no risk to use out of range indices.
Asked: 2021-03-17 11:19:29 +0100
Seen: 337 times
Last updated: Mar 17 '21
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