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why sagemath returns 2 solution instead of one

asked 2020-07-04 19:49:23 +0100

lolora gravatar image

when I run the expression

solve([x>=3, x >=5, x < 8],x)

It returns

[[5 < x, x < 8], [x == 5]]

But I'm hoping that it would return

[[5 <= x, x < 8]]

How do I get my expected value?

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answered 2020-07-05 08:41:12 +0100

Emmanuel Charpentier gravatar image

A possible alternative :

sage: solve([x>=3, x >=5, x < 8],x, algorithm="sympy")
[[5 <= x, x < 8]]

HTH,

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answered 2020-07-04 20:32:07 +0100

Cyrille gravatar image

updated 2020-07-04 20:36:11 +0100

Sage gives the hand to Maxima to solve a Fourier-Motzkin list of inequalities. And if there is an explicit solution in equality terms Maxima gives it. Because if $x= 5$ necessarily $x<8$. There is no more to say. Try successively

solve([x <= 5, x<8],x)

solve([x < 5, x<8],x)
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Asked: 2020-07-04 19:49:23 +0100

Seen: 458 times

Last updated: Jul 05 '20