I have a list of number say
l = [1.25, 2.46, 3.99, 4, 5, 6, 7.12, 8.76 ,9.34, 10.42, 11.5, 12.]
I have a list of real intervals
Cl=[[0, 5),[5, 10),[10, 15)]
How to create sublists of l according to the intervals in Cl ? If I was work in N there will be no difficulties.
I have found a solution, but I wonder if it is the best. As I am not Pierre de Fermat, I will give it
Ac=[[x for x in l if bool(x in cl[j])==True] for j in range(len(Cl))]
Your solution is a brute force approach which does not take into account that the lists of numbers and intervals are ordered. There are surely better solutions if both lists are large. By the way, note that your syntax for intervals is not valid. Try this:
l = [1.25, 2.46, 3.99, 4, 5, 6, 7.12, 8.76 ,9.34, 10.42, 11.5, 12.]
Cl = [[0, 5], [5, 10], [10, 15]]
[[x for x in l if c[0]<=x<c[1]] for c in Cl]
Asked: 2020-06-18 10:49:52 +0100
Seen: 263 times
Last updated: Jun 18 '20
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.
