Possible bug when a symbolic function is declared twice
 
  
 
  
 
 
 
 
 
 
    
        
        asked 4 years ago  
 
 Florentin Jaffredo gravatar image  
 
 
 
 
    
        
        updated 1 year ago  
 
 FrédéricC gravatar image  
 
 
 
 
 
I don't understand the output of the following code:
 
sage: f = function('f')
sage: f(x).operator() is f
True
sage: f = function('f')
sage: f(x).operator() is f
False
 
Is that the intended behavior?
 
It seems that operator returns the first symbolic function defined with this name, not the actual operator. This is problematic for me  because it means there are some cells in my notebook I can only run once, so I have to restart the kernel everytime I want to press "run all".
 
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Comments
1
At the very least, there is some inconsistency between var and  function: both of them inject names in the global namespace, but function creates a new object at each call:
sage: var('a') is var('a')
True
sage: function('f') is function('f')
False
eric_g gravatar imageeric_g (
    
        4 years ago
    )
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