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subs: why it accepts one form but not the other?

asked 2020-06-09 20:51:05 -0500

curios_mind gravatar image

updated 2020-06-09 21:09:11 -0500

Hello,

Consider the following expression

y=function("y")(x)
z=-3*diff(y,x)/y^4

I would like to replace diff(y,x)/y^4 by, say, 2/5

I tried,

z.subs(diff(y,x)/y^4==2/5).show()

But this didn't work (threw back at me the original expression)

I tried to replace y^4 by 5, and to do that I did

z.subs(y^4==5).show()

It didn't work. However,

z.subs(1/y^4==5).show()

worked!. I am confused!

If I tried to replace just y with 5^(1/4)

z.subs(y==(5)^(1/4)).show()

it worked! so it cannot replace y^4 with 5, but it can replace y with (5)^1/4.

To get what I want I finally did

z.subs(diff(y,x)==2).subs(1/y^4==5).show()

I got this by trial and error. Shouldn't the first one

z.subs(diff(y,x)/y^4==2/5).show()

have worked in the first place? What is the logic behind this that it didn't work?

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answered 2020-06-10 10:41:02 -0500

eric_g gravatar image

updated 2020-06-10 10:41:44 -0500

The general strategy to replace a composed expression like diff(y, x)/y^4 is to replace only a simple part of it by an equivalent expression. In your case:

sage: y = function('y')
sage: Y = y(x)
sage: z = -3*diff(Y, x)/Y^4
sage: z.subs(diff(Y, x) == 2/5*Y^4)
-6/5
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Asked: 2020-06-09 20:51:05 -0500

Seen: 53 times

Last updated: Jun 10