I was just wondering what can I do to convert the binary digits (for ex. ASCII) shown below to integers.
sage: from sage.crypto.util import ascii_to_bin
sage: from sage.crypto.util import ascii_integer
sage: bin=BinaryStrings()
sage: B=bin.encoding("A"); B
01000001
sage: ascii_integer(B)
65
sage: parent(B)
Free binary string monoid
sage: parent(ascii_integer(B)) <type 'int'="">
sage:
Let me just add a warning: if you want to make B an integer, as in your previous question, you can first try:
sage: ZZ(str(B))
262145
which looks pretty weird. This is due to the fact that the number:
sage: str(B)
'01000001'
starts with a 0, indicating that it should undertand the representation to be in octal, while you want it in binary. Fortunately, you can specify the base in the conversion:
sage: b = ZZ(str(B), base=2) ; b
65
sage: b.parent()
Integer Ring
Asked: 2020-06-02 12:55:46 +0100
Seen: 546 times
Last updated: Jun 02 '20
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