Desattribution of a value to a variable
Suppose I have attributed to a the value 3. But for the following operation I want to use anew a as a variable how should I operate, redefine a ?
A Python name is just a pointer to a Python/Sage object:
sage: a = 3
sage: a+a
6
Now, if you redefine it, it will just point to the new object:
sage: a = 12
sage: a
12
sage: a^2
144
If you want the symbol a (not to be confused with the Python name a), you can do:
sage: SR.var('a')
a
Any Python name can point to such symbol:
sage: b = SR.var('a')
sage: b
a
sage: (b+1)^2
(a + 1)^2
What confuses most people is that the shortcut:
sage: var('a')
a
both returns the symbol a and let the Python name a point to this symbol, in particular, it removes the previous pointer of the Python name a :
sage: a # this a is a Python name
a # this a is a symbol, pointed bythe previous Python name
Asked: 2020-05-12 16:53:36 +0100
Seen: 267 times
Last updated: May 12 '20
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