I would like to construct a function with return the string "Vrai" or the string 'Faux' selon qu x>y ou x<=y. I have tried
cond(x, y)= if bool(x<y)='True' then Print("Accepté") else Print("Rejeté")but it leads to an error
To construct a function, you have to use def Python statement.
def cond(x, y):
if x<y:
print("Accepté")
else:
print("Rejeté")EDIT given the comment, it seems that you do not want to only print the result, but you want the function to return the string. So, here it is:
def cond(x, y):
if x<y:
return "Accepté"
else:
return "Rejeté"All this is pure Python. Let me suggest to read some introductions about this generic language, since Sage is based on it, and you will benefit a lot to make clever constructions out of Sage mathematical bricks.
tmonteil thanks for your reactivity
A subsequent consequence of your formula. I have an error with the following code
a=1
b=2
c=3
d=4
e=5
f=6
essay = [[cond(a,b)],[cond(c,d)],[cond(e,f)]]
table(essay,header_row=[r'A',r'B',r'C')and when it works results are not displayed in the table
To complement @tmonteil's answer.
In some cases a lambda function is also okay.
It takes up less lines than a def function.
sage: cond = lambda x, y: "Accepté" if bool(x<y) else "Rejeté"Then:
sage: a, b, c, d, e, f = [1 .. 6]
sage: essay = [[cond(a, b)], [cond(c, d)], [cond(e, f)]]
sage: hc = ['test', r'A', r'B', r'C']
sage: table(essay, header_row=['résultat'], header_column=hc)
test | résultat
+------+----------+
A | Accepté
B | Accepté
C | AcceptéAsked: 4 years ago
Seen: 503 times
Last updated: May 06 '20
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.
Could you please edit the question to make it more consistent:
I am confused to be able to write such inconsistent english